Equation: y-y1=k(x-x1)
Where (x1, y1) is the coordinate of a point on the coordinate system that is too straight, and k is the slope of the line.
Derivation: If the straight line L1 passes through the point P1 (x1, y1) and the slope is k, the L1 equation is obtained.
Let P (x, y) be any point on the line different from point P1. The slope of line PP1 should be equal to the slope of line L1, based on the slope of the line passing through two points.
k=(y-y1)/(x-x1) (and: x≠x1)
So, the line L1:
y-y1=k(x-x1)
X1: 4;
Y1: 2
Slope(m): 5
Click "calculate" to output the result.
Equation: 5x -y -18=0.
Powered by TorCMS (https://github.com/bukun/TorCMS).