发布日期 ： 2019-10-31 03:18:12 UTC
分类 ： Algebraic
Straight line 1: A1x+B1y+C1=0,
Straight line 2： A2x+B2y+C2=0,
Then the intersection point of two straight lines can be calculated as follows:
Results:
x=(B<sub>1</sub>C<sub>2</sub>-B<sub>2</sub>C<sub>1</sub>)/(B<sub>2</sub>A<sub>1</sub>-B<sub>1</sub>A<sub>2</sub>)
y=(A<sub>1</sub>C<sub>2</sub>-C<sub>1</sub>A<sub>2</sub>)/(B<sub>1</sub>A<sub>2</sub>-A<sub>1</sub>B<sub>2</sub>)
5X + 8Y = 12
-4X + 3Y = 6
Click "calculate" to output the result
X coordinate of intersection point: -0.2553,
Y coordinate of intersection point: 1.6596,
Results:
Straight line 1: 5x + 8y = 12
Straight line 2: -4x + 3Y = 6
Intersection: -0.2553,1.6596