The total emission of total smoke G is calculated as follows:
$$ G=B \times G $$
$$ G=1.14 \frac {QL}{4182}-0.25+1.0161(α-1)V0 $$
$$ V0=1.09 \frac {QL}{4182}-0.25 $$
In the formula:
G total - total smoke emissions, m 3 / h;
B-fuel consumption, m3/h;
G-flue volume, m3/m3
QL-natural gas low calorific value, take 8500kcal/m3, ie 35700KJ/m3;
-- excess air coefficient, Α=Α0+ΔΑ, take 1.4;
V0 - theoretical air demand, m 3/m3.
Powered by TorCMS (https://github.com/bukun/TorCMS).